Optimal. Leaf size=221 \[ f^2 x \log \left (c \left (d+e x^2\right )^p\right )+\frac{2}{3} f g x^3 \log \left (c \left (d+e x^2\right )^p\right )+\frac{1}{5} g^2 x^5 \log \left (c \left (d+e x^2\right )^p\right )-\frac{4 d^{3/2} f g p \tan ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d}}\right )}{3 e^{3/2}}-\frac{2 d^2 g^2 p x}{5 e^2}+\frac{2 d^{5/2} g^2 p \tan ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d}}\right )}{5 e^{5/2}}+\frac{2 \sqrt{d} f^2 p \tan ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d}}\right )}{\sqrt{e}}+\frac{4 d f g p x}{3 e}+\frac{2 d g^2 p x^3}{15 e}-2 f^2 p x-\frac{4}{9} f g p x^3-\frac{2}{25} g^2 p x^5 \]
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Rubi [A] time = 0.170613, antiderivative size = 221, normalized size of antiderivative = 1., number of steps used = 13, number of rules used = 6, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.273, Rules used = {2471, 2448, 321, 205, 2455, 302} \[ f^2 x \log \left (c \left (d+e x^2\right )^p\right )+\frac{2}{3} f g x^3 \log \left (c \left (d+e x^2\right )^p\right )+\frac{1}{5} g^2 x^5 \log \left (c \left (d+e x^2\right )^p\right )-\frac{4 d^{3/2} f g p \tan ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d}}\right )}{3 e^{3/2}}-\frac{2 d^2 g^2 p x}{5 e^2}+\frac{2 d^{5/2} g^2 p \tan ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d}}\right )}{5 e^{5/2}}+\frac{2 \sqrt{d} f^2 p \tan ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d}}\right )}{\sqrt{e}}+\frac{4 d f g p x}{3 e}+\frac{2 d g^2 p x^3}{15 e}-2 f^2 p x-\frac{4}{9} f g p x^3-\frac{2}{25} g^2 p x^5 \]
Antiderivative was successfully verified.
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Rule 2471
Rule 2448
Rule 321
Rule 205
Rule 2455
Rule 302
Rubi steps
\begin{align*} \int \left (f+g x^2\right )^2 \log \left (c \left (d+e x^2\right )^p\right ) \, dx &=\int \left (f^2 \log \left (c \left (d+e x^2\right )^p\right )+2 f g x^2 \log \left (c \left (d+e x^2\right )^p\right )+g^2 x^4 \log \left (c \left (d+e x^2\right )^p\right )\right ) \, dx\\ &=f^2 \int \log \left (c \left (d+e x^2\right )^p\right ) \, dx+(2 f g) \int x^2 \log \left (c \left (d+e x^2\right )^p\right ) \, dx+g^2 \int x^4 \log \left (c \left (d+e x^2\right )^p\right ) \, dx\\ &=f^2 x \log \left (c \left (d+e x^2\right )^p\right )+\frac{2}{3} f g x^3 \log \left (c \left (d+e x^2\right )^p\right )+\frac{1}{5} g^2 x^5 \log \left (c \left (d+e x^2\right )^p\right )-\left (2 e f^2 p\right ) \int \frac{x^2}{d+e x^2} \, dx-\frac{1}{3} (4 e f g p) \int \frac{x^4}{d+e x^2} \, dx-\frac{1}{5} \left (2 e g^2 p\right ) \int \frac{x^6}{d+e x^2} \, dx\\ &=-2 f^2 p x+f^2 x \log \left (c \left (d+e x^2\right )^p\right )+\frac{2}{3} f g x^3 \log \left (c \left (d+e x^2\right )^p\right )+\frac{1}{5} g^2 x^5 \log \left (c \left (d+e x^2\right )^p\right )+\left (2 d f^2 p\right ) \int \frac{1}{d+e x^2} \, dx-\frac{1}{3} (4 e f g p) \int \left (-\frac{d}{e^2}+\frac{x^2}{e}+\frac{d^2}{e^2 \left (d+e x^2\right )}\right ) \, dx-\frac{1}{5} \left (2 e g^2 p\right ) \int \left (\frac{d^2}{e^3}-\frac{d x^2}{e^2}+\frac{x^4}{e}-\frac{d^3}{e^3 \left (d+e x^2\right )}\right ) \, dx\\ &=-2 f^2 p x+\frac{4 d f g p x}{3 e}-\frac{2 d^2 g^2 p x}{5 e^2}-\frac{4}{9} f g p x^3+\frac{2 d g^2 p x^3}{15 e}-\frac{2}{25} g^2 p x^5+\frac{2 \sqrt{d} f^2 p \tan ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d}}\right )}{\sqrt{e}}+f^2 x \log \left (c \left (d+e x^2\right )^p\right )+\frac{2}{3} f g x^3 \log \left (c \left (d+e x^2\right )^p\right )+\frac{1}{5} g^2 x^5 \log \left (c \left (d+e x^2\right )^p\right )-\frac{\left (4 d^2 f g p\right ) \int \frac{1}{d+e x^2} \, dx}{3 e}+\frac{\left (2 d^3 g^2 p\right ) \int \frac{1}{d+e x^2} \, dx}{5 e^2}\\ &=-2 f^2 p x+\frac{4 d f g p x}{3 e}-\frac{2 d^2 g^2 p x}{5 e^2}-\frac{4}{9} f g p x^3+\frac{2 d g^2 p x^3}{15 e}-\frac{2}{25} g^2 p x^5+\frac{2 \sqrt{d} f^2 p \tan ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d}}\right )}{\sqrt{e}}-\frac{4 d^{3/2} f g p \tan ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d}}\right )}{3 e^{3/2}}+\frac{2 d^{5/2} g^2 p \tan ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d}}\right )}{5 e^{5/2}}+f^2 x \log \left (c \left (d+e x^2\right )^p\right )+\frac{2}{3} f g x^3 \log \left (c \left (d+e x^2\right )^p\right )+\frac{1}{5} g^2 x^5 \log \left (c \left (d+e x^2\right )^p\right )\\ \end{align*}
Mathematica [A] time = 0.11959, size = 151, normalized size = 0.68 \[ \frac{\sqrt{e} x \left (15 e^2 \left (15 f^2+10 f g x^2+3 g^2 x^4\right ) \log \left (c \left (d+e x^2\right )^p\right )-2 p \left (45 d^2 g^2-15 d e g \left (10 f+g x^2\right )+e^2 \left (225 f^2+50 f g x^2+9 g^2 x^4\right )\right )\right )+30 \sqrt{d} p \left (3 d^2 g^2-10 d e f g+15 e^2 f^2\right ) \tan ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d}}\right )}{225 e^{5/2}} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.533, size = 686, normalized size = 3.1 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.09358, size = 922, normalized size = 4.17 \begin{align*} \left [-\frac{18 \, e^{2} g^{2} p x^{5} + 10 \,{\left (10 \, e^{2} f g - 3 \, d e g^{2}\right )} p x^{3} - 15 \,{\left (15 \, e^{2} f^{2} - 10 \, d e f g + 3 \, d^{2} g^{2}\right )} p \sqrt{-\frac{d}{e}} \log \left (\frac{e x^{2} + 2 \, e x \sqrt{-\frac{d}{e}} - d}{e x^{2} + d}\right ) + 30 \,{\left (15 \, e^{2} f^{2} - 10 \, d e f g + 3 \, d^{2} g^{2}\right )} p x - 15 \,{\left (3 \, e^{2} g^{2} p x^{5} + 10 \, e^{2} f g p x^{3} + 15 \, e^{2} f^{2} p x\right )} \log \left (e x^{2} + d\right ) - 15 \,{\left (3 \, e^{2} g^{2} x^{5} + 10 \, e^{2} f g x^{3} + 15 \, e^{2} f^{2} x\right )} \log \left (c\right )}{225 \, e^{2}}, -\frac{18 \, e^{2} g^{2} p x^{5} + 10 \,{\left (10 \, e^{2} f g - 3 \, d e g^{2}\right )} p x^{3} - 30 \,{\left (15 \, e^{2} f^{2} - 10 \, d e f g + 3 \, d^{2} g^{2}\right )} p \sqrt{\frac{d}{e}} \arctan \left (\frac{e x \sqrt{\frac{d}{e}}}{d}\right ) + 30 \,{\left (15 \, e^{2} f^{2} - 10 \, d e f g + 3 \, d^{2} g^{2}\right )} p x - 15 \,{\left (3 \, e^{2} g^{2} p x^{5} + 10 \, e^{2} f g p x^{3} + 15 \, e^{2} f^{2} p x\right )} \log \left (e x^{2} + d\right ) - 15 \,{\left (3 \, e^{2} g^{2} x^{5} + 10 \, e^{2} f g x^{3} + 15 \, e^{2} f^{2} x\right )} \log \left (c\right )}{225 \, e^{2}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.32844, size = 271, normalized size = 1.23 \begin{align*} \frac{2 \,{\left (3 \, d^{3} g^{2} p - 10 \, d^{2} f g p e + 15 \, d f^{2} p e^{2}\right )} \arctan \left (\frac{x e^{\frac{1}{2}}}{\sqrt{d}}\right ) e^{\left (-\frac{5}{2}\right )}}{15 \, \sqrt{d}} + \frac{1}{225} \,{\left (45 \, g^{2} p x^{5} e^{2} \log \left (x^{2} e + d\right ) - 18 \, g^{2} p x^{5} e^{2} + 45 \, g^{2} x^{5} e^{2} \log \left (c\right ) + 30 \, d g^{2} p x^{3} e + 150 \, f g p x^{3} e^{2} \log \left (x^{2} e + d\right ) - 100 \, f g p x^{3} e^{2} + 150 \, f g x^{3} e^{2} \log \left (c\right ) - 90 \, d^{2} g^{2} p x + 300 \, d f g p x e + 225 \, f^{2} p x e^{2} \log \left (x^{2} e + d\right ) - 450 \, f^{2} p x e^{2} + 225 \, f^{2} x e^{2} \log \left (c\right )\right )} e^{\left (-2\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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